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I've endlessly looked for this and somehow nothing has solved this simple problem.
I have a dataframe called Prices in which there are 4 columns, one of which is a list of historical dates - the other 3 are lists of prices for products.
1 10/10/2016 53.14 50.366 51.87 2 07/10/2016 51.93 49.207 50.38 3 06/10/2016 52.51 49.655 50.98 4 05/10/2016 51.86 49.076 50.38 5 04/10/2016 50.87 48.186 49.3 6 03/10/2016 50.89 48.075 49.4 7 30/09/2016 50.19 47.384 48.82 8 29/09/2016 49.81 46.924 48.4 9 28/09/2016 49.24 46.062 47.65 10 27/09/2016 46.52 43.599 45.24 The list is 252 prices long. How can I have my output stored with the latest date at the bottom of the list and the corresponding prices listed with the latest prices at the bottom of the list?
846
You can rotate the data. frame so that the rows become the columns and the columns become the rows. That is, you transpose the rows and columns. You simply use the t() command.
To reverse a list in R programming, call rev() function and pass given list as argument to it. rev() function returns returns a new list with the contents of given list in reversed order.
rev() function in R Language is used to return the reverse version of data objects. The data objects can be defined as Vectors, Data Frames by Columns & by Rows, etc.
Another tidyverse solution and I think the simplest one is:
df %>% map_df(rev)
or using just purrr::map_df we can do map_df(df, rev).
151
If you just want to reverse the order of the rows in a dataframe, you can do the following:
df<- df[seq(dim(df)[1],1),] If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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