I am trying to retrieve the most repeated value in a particular column present in a data frame.Here is my sample data and code below.A
data("Forbes2000", package = "HSAUR")
head(Forbes2000)
rank name country category sales profits assets marketvalue
1 1 Citigroup United States Banking 94.71 17.85 1264.03 255.30
2 2 General Electric United States Conglomerates 134.19 15.59 626.93 328.54
3 3 American Intl Group United States Insurance 76.66 6.46 647.66 194.87
4 4 ExxonMobil United States Oil & gas operations 222.88 20.96 166.99 277.02
5 5 BP United Kingdom Oil & gas operations 232.57 10.27 177.57 173.54
6 6 Bank of America United States Banking 49.01 10.81 736.45 117.55
As per my sample data I need to return the most repeated category which is Insurance.
subset(subset(Forbes2000,country=="Bermuda")
tail(names(sort(table(Forbes2000$category))), 1)
In case two or more categories may be tied for most frequent, use something like this:
x <- c("Insurance", "Insurance", "Capital Goods", "Food markets", "Food markets")
tt <- table(x)
names(tt[tt==max(tt)])
[1] "Food markets" "Insurance"
Another way with the data.table package, which is faster for large data sets:
set.seed(1)
x=sample(seq(1,100), 5000000, replace = TRUE)
method 1 (solution proposed above)
start.time <- Sys.time()
tt <- table(x)
names(tt[tt==max(tt)])
end.time <- Sys.time()
time.taken <- end.time - start.time
time.taken
Time difference of 4.883488 secs
method 2 (DATA TABLE)
start.time <- Sys.time()
ds <- data.table( x )
setkey(ds, x)
sorted <- ds[,.N,by=list(x)]
most_repeated_value <- sorted[order(-N)]$x[1]
most_repeated_value
end.time <- Sys.time()
time.taken <- end.time - start.time
time.taken
Time difference of 0.328033 secs
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