how to remove first two words of a strings output

Question

I want to remove the first two words that come up in my output string. this string is also within another string.

What I have:

for servers in `ls /data/field`    
do    
  string=`cat /data/field/$servers/time`

This sends this text:

00:00 down server

I would like to remove "00:00 down" so that it only displays "server".

I have tried using cut -d ' ' -f2- $string which ends up just removing directories that the command searches.

Any ideas?

Answer 1

Please, do the things properly :

for servers in /data/field/*; do
    string=$(cut -d" "  -f3- /data/field/$servers/time)
    echo "$string"
done

• backticks are deprecated in 2014 in favor of the form $( )
• don't parse ls output, use glob instead like I do with data/field/*

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