How to Remove Every Other Element in an Array in Swift?

Question

So say I have an array:

var stringArray = ["a","b","c","d","e","f","g","h","i","j"]

Now, how do I delete "a", "c", "e", "g", and "i" (all the even number indexes from the array)?

Thanks!

Answer 1

Instead of using C-style for-loops (which are set to be deprecated in an upcoming version of Swift), you could accomplish this using strides:

var result = [String]()
for i in stride(from: 1, through: stringArray.count - 1, by: 2) {
    result.append(stringArray[i])
}

Or for an even more functional solution,

let result = stride(from: 1, to: stringArray.count - 1, by: 2).map { stringArray[$0] }