To remove element from array in forEach loop with JavaScript, we can use the array splice method. const review = ["a", "b", "c", "b", "a"]; review. forEach((item, index, arr) => { if (item === "a") { arr. splice(index, 1); } });
pop() function: This method is use to remove elements from the end of an array. shift() function: This method is use to remove elements from the start of an array. splice() function: This method is use to remove elements from the specific index of an array.
Use the for Loop to Remove Element From Array and Shift in Java. In this approach, we use multiple for loops to loop over all elements of the arr and check for the element that we want to remove. When the element to be deleted is found, we create a new Array newArr with the size arr. length-1 .
To change the value of all elements in an array:Use the forEach() method to iterate over the array. The method takes a function that gets invoked with the array element, its index and the array itself. Use the index of the current iteration to change the corresponding array element.
It looks like you are trying to do this?
Iterate and mutate an array using Array.prototype.splice
var pre = document.getElementById('out');
function log(result) {
pre.appendChild(document.createTextNode(result + '\n'));
}
var review = ['a', 'b', 'c', 'b', 'a'];
review.forEach(function(item, index, object) {
if (item === 'a') {
object.splice(index, 1);
}
});
log(review);
<pre id="out"></pre>
Which works fine for simple case where you do not have 2 of the same values as adjacent array items, other wise you have this problem.
var pre = document.getElementById('out');
function log(result) {
pre.appendChild(document.createTextNode(result + '\n'));
}
var review = ['a', 'a', 'b', 'c', 'b', 'a', 'a'];
review.forEach(function(item, index, object) {
if (item === 'a') {
object.splice(index, 1);
}
});
log(review);
<pre id="out"></pre>
So what can we do about this problem when iterating and mutating an array? Well the usual solution is to work in reverse. Using ES3 while but you could use for sugar if preferred
var pre = document.getElementById('out');
function log(result) {
pre.appendChild(document.createTextNode(result + '\n'));
}
var review = ['a' ,'a', 'b', 'c', 'b', 'a', 'a'],
index = review.length - 1;
while (index >= 0) {
if (review[index] === 'a') {
review.splice(index, 1);
}
index -= 1;
}
log(review);
<pre id="out"></pre>
Ok, but you wanted to use ES5 iteration methods. Well and option would be to use Array.prototype.filter but this does not mutate the original array but creates a new one, so while you can get the correct answer it is not what you appear to have specified.
We could also use ES5 Array.prototype.reduceRight, not for its reducing property by rather its iteration property, i.e. iterate in reverse.
var pre = document.getElementById('out');
function log(result) {
pre.appendChild(document.createTextNode(result + '\n'));
}
var review = ['a', 'a', 'b', 'c', 'b', 'a', 'a'];
review.reduceRight(function(acc, item, index, object) {
if (item === 'a') {
object.splice(index, 1);
}
}, []);
log(review);
<pre id="out"></pre>
Or we could use ES5 Array.protoype.indexOf like so.
var pre = document.getElementById('out');
function log(result) {
pre.appendChild(document.createTextNode(result + '\n'));
}
var review = ['a', 'a', 'b', 'c', 'b', 'a', 'a'],
index = review.indexOf('a');
while (index !== -1) {
review.splice(index, 1);
index = review.indexOf('a');
}
log(review);
<pre id="out"></pre>
But you specifically want to use ES5 Array.prototype.forEach, so what can we do? Well we need to use Array.prototype.slice to make a shallow copy of the array and Array.prototype.reverse so we can work in reverse to mutate the original array.
var pre = document.getElementById('out');
function log(result) {
pre.appendChild(document.createTextNode(result + '\n'));
}
var review = ['a', 'a', 'b', 'c', 'b', 'a', 'a'];
review.slice().reverse().forEach(function(item, index, object) {
if (item === 'a') {
review.splice(object.length - 1 - index, 1);
}
});
log(review);
<pre id="out"></pre>
Finally ES6 offers us some further alternatives, where we do not need to make shallow copies and reverse them. Notably we can use Generators and Iterators. However support is fairly low at present.
var pre = document.getElementById('out');
function log(result) {
pre.appendChild(document.createTextNode(result + '\n'));
}
function* reverseKeys(arr) {
var key = arr.length - 1;
while (key >= 0) {
yield key;
key -= 1;
}
}
var review = ['a', 'a', 'b', 'c', 'b', 'a', 'a'];
for (var index of reverseKeys(review)) {
if (review[index] === 'a') {
review.splice(index, 1);
}
}
log(review);
<pre id="out"></pre>
Something to note in all of the above is that, if you were stripping NaN from the array then comparing with equals is not going to work because in Javascript NaN === NaN
is false. But we are going to ignore that in the solutions as it it yet another unspecified edge case.
So there we have it, a more complete answer with solutions that still have edge cases. The very first code example is still correct but as stated, it is not without issues.
Use Array.prototype.filter
instead of forEach
:
var pre = document.getElementById('out');
function log(result) {
pre.appendChild(document.createTextNode(result + '\n'));
}
var review = ['a', 'b', 'c', 'b', 'a', 'e'];
review = review.filter(item => item !== 'a');
log(review);
Although Xotic750's answer provides several good points and possible solutions, sometimes simple is better.
You know the array being iterated on is being mutated in the iteration itself (i.e. removing an item => index changes), thus the simplest logic is to go backwards in an old fashioned for
(à la C language):
let arr = ['a', 'a', 'b', 'c', 'b', 'a', 'a'];
for (let i = arr.length - 1; i >= 0; i--) {
if (arr[i] === 'a') {
arr.splice(i, 1);
}
}
document.body.append(arr.join());
If you really think about it, a forEach
is just syntactic sugar for a for
loop... So if it's not helping you, just please stop breaking your head against it.
You could also use indexOf instead to do this
var i = review.indexOf('\u2022 \u2022 \u2022');
if (i !== -1) review.splice(i,1);
I understood that you want to remove from the array using a condition and have another array that has items removed from the array. Is right?
How about this?
var review = ['a', 'b', 'c', 'ab', 'bc'];
var filtered = [];
for(var i=0; i < review.length;) {
if(review[i].charAt(0) == 'a') {
filtered.push(review.splice(i,1)[0]);
}else{
i++;
}
}
console.log("review", review);
console.log("filtered", filtered);
Hope this help...
By the way, I compared 'for-loop' to 'forEach'.
If remove in case a string contains 'f', a result is different.
var review = ["of", "concat", "copyWithin", "entries", "every", "fill", "filter", "find", "findIndex", "flatMap", "flatten", "forEach", "includes", "indexOf", "join", "keys", "lastIndexOf", "map", "pop", "push", "reduce", "reduceRight", "reverse", "shift", "slice", "some", "sort", "splice", "toLocaleString", "toSource", "toString", "unshift", "values"];
var filtered = [];
for(var i=0; i < review.length;) {
if( review[i].includes('f')) {
filtered.push(review.splice(i,1)[0]);
}else {
i++;
}
}
console.log("review", review);
console.log("filtered", filtered);
/**
* review [ "concat", "copyWithin", "entries", "every", "includes", "join", "keys", "map", "pop", "push", "reduce", "reduceRight", "reverse", "slice", "some", "sort", "splice", "toLocaleString", "toSource", "toString", "values"]
*/
console.log("========================================================");
review = ["of", "concat", "copyWithin", "entries", "every", "fill", "filter", "find", "findIndex", "flatMap", "flatten", "forEach", "includes", "indexOf", "join", "keys", "lastIndexOf", "map", "pop", "push", "reduce", "reduceRight", "reverse", "shift", "slice", "some", "sort", "splice", "toLocaleString", "toSource", "toString", "unshift", "values"];
filtered = [];
review.forEach(function(item,i, object) {
if( item.includes('f')) {
filtered.push(object.splice(i,1)[0]);
}
});
console.log("-----------------------------------------");
console.log("review", review);
console.log("filtered", filtered);
/**
* review [ "concat", "copyWithin", "entries", "every", "filter", "findIndex", "flatten", "includes", "join", "keys", "map", "pop", "push", "reduce", "reduceRight", "reverse", "slice", "some", "sort", "splice", "toLocaleString", "toSource", "toString", "values"]
*/
And remove by each iteration, also a result is different.
var review = ["of", "concat", "copyWithin", "entries", "every", "fill", "filter", "find", "findIndex", "flatMap", "flatten", "forEach", "includes", "indexOf", "join", "keys", "lastIndexOf", "map", "pop", "push", "reduce", "reduceRight", "reverse", "shift", "slice", "some", "sort", "splice", "toLocaleString", "toSource", "toString", "unshift", "values"];
var filtered = [];
for(var i=0; i < review.length;) {
filtered.push(review.splice(i,1)[0]);
}
console.log("review", review);
console.log("filtered", filtered);
console.log("========================================================");
review = ["of", "concat", "copyWithin", "entries", "every", "fill", "filter", "find", "findIndex", "flatMap", "flatten", "forEach", "includes", "indexOf", "join", "keys", "lastIndexOf", "map", "pop", "push", "reduce", "reduceRight", "reverse", "shift", "slice", "some", "sort", "splice", "toLocaleString", "toSource", "toString", "unshift", "values"];
filtered = [];
review.forEach(function(item,i, object) {
filtered.push(object.splice(i,1)[0]);
});
console.log("-----------------------------------------");
console.log("review", review);
console.log("filtered", filtered);
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