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I have a collections.defaultdict as follows:
mydict = defaultdict(lambda:0)
mydict['stock1'] = 1.11
mydict['stock2'] = 2.22
mydict['stock3'] = 3.33
Now I want to remove the second item completely, how can I do that?
Maybe there is little seens to remove that but just simply set it to zero as follow:
mydict['stock2'] = 0
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A defaultdict works exactly like a normal dict, but it is initialized with a function (“default factory”) that takes no arguments and provides the default value for a nonexistent key. A defaultdict will never raise a KeyError. Any key that does not exist gets the value returned by the default factory.
Finally, using a defaultdict to handle missing keys can be faster than using dict.
DefaultDict ,on append elements, maintain keys sorted in the order of addition [duplicate]
A defaultdict can be created by giving its declaration an argument that can have three values; list, set or int. According to the specified data type, the dictionary is created and when any key, that does not exist in the defaultdict is added or accessed, it is assigned a default value as opposed to giving a KeyError .
See the documentation, it's just like the ordinary dictionary. You can use either:
del mydict['stock2']mydict.pop('stock2')
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