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I'm trying to run a query that has a few columns that are a CLOB datatype. If i run the query like normal, all of those fields just have (CLOB) as the value.
I tried using DBMS_LOB.substr(column) and i get the error
ORA-06502: PL/SQL: numeric or value error: character string buffer too small How can i query the CLOB column?
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When getting the substring of a CLOB column and using a query tool that has size/buffer restrictions sometimes you would need to set the BUFFER to a larger size. For example while using SQL Plus use the SET BUFFER 10000 to set it to 10000 as the default is 4000. Running the DBMS_LOB.
You can read CLOB value (character stream data) from a table using getCharacterStream() or getClob() methods of the ResultSet interface. These methods accept an integer value representing the index of the required column (or, a String value representing its name) and, reads CLOB data from it.
select dbms_lob. substr(clob_filed, 1000000, 1) from exportlog; I run this sql in sql developer and sqlplus in command prompt. both always return NULL.
This works
select DBMS_LOB.substr(myColumn, 3000) from myTable When getting the substring of a CLOB column and using a query tool that has size/buffer restrictions sometimes you would need to set the BUFFER to a larger size. For example while using SQL Plus use the SET BUFFER 10000 to set it to 10000 as the default is 4000.
Running the DBMS_LOB.substr command you can also specify the amount of characters you want to return and the offset from which. So using DBMS_LOB.substr(column, 3000) might restrict it to a small enough amount for the buffer.
See oracle documentation for more info on the substr command
DBMS_LOB.SUBSTR ( lob_loc IN CLOB CHARACTER SET ANY_CS, amount IN INTEGER := 32767, offset IN INTEGER := 1) RETURN VARCHAR2 CHARACTER SET lob_loc%CHARSET;
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