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If a user enters an integer like 4210 for example, how can I put each digit of that integer in a vector in C++?
400
asked Apr 02 '14 17:04
Simplest would be to input it as a string and then just iterate that string, pushing every element into a vector. After you have each digit separately it's trivial to lexically cast it to integer for vector<int>.
An array is created using square brackets ( [ and ] ). For example, an array of numbers can be created as follows: let arr: number[] = []; To create an array of values, you simply add square brackets following the type of the values that will be stored in the array: number[] is the type for a number array.
There are two types of vectors: Atomic vectors, of which there are six types: logical, integer, double, character, complex, and raw. Integer and double vectors are collectively known as numeric vectors.
It can be done like:
std::vector<int> numbers;
int x;
std::cin >> x;
while(x>0)
{
numbers.push_back(x%10);
x/=10;
}
std::reverse(numbers.begin(), numbers.end());
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