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I have something like this:
<img style="background:url(/theRealImage.jpg) no-repate 0 0; height:90px; width:92px;") src="notTheRealImage.jpg"/>
I am using beautifulsoup to parse the html. Is there away to pull out the "url" in the "background" css attribute?
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You've got a couple options- quick and dirty or the Right Way. The quick and dirty way (which will break easily if the markup is changed) looks like
>>> from BeautifulSoup import BeautifulSoup
>>> import re
>>> soup = BeautifulSoup('<html><body><img style="background:url(/theRealImage.jpg) no-repate 0 0; height:90px; width:92px;") src="notTheRealImage.jpg"/></body></html>')
>>> style = soup.find('img')['style']
>>> urls = re.findall('url\((.*?)\)', style)
>>> urls
[u'/theRealImage.jpg']
Obviously, you'll have to play with that to get it to work with multiple img tags.
The Right Way, since I'd feel awful suggesting someone use regex on a CSS string :), uses a CSS parser. cssutils, a library I just found on Google and available on PyPi, looks like it might do the job.
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