How do I declare a templated type that refers to itself?
template <class T = Animal> class Animal
{
public:
T getChild ();
}
With this, I get a compiler error concerning a missing type specifier. I tried to forward-declare Animal
, without success.
I am trying to impose a type constraint. A Lion
can only have a Lion
as a child, a Bear
has a Bear
, and so on.
EDIT
I'll post part of the actual class. It is a template for classes that can appear in a linked list:
template <class T = Linked<T> > class Linked
{
private:
T* m_prev;
T* m_next;
}
I want to enforce that the class can only point to object of the same class (or a subclass).
In this case, you need to specify some type parameter to Animal in your typename definition, or else it would be an "infinite recursion" in the type construction:
template<class T> class Animal;//you'll need this forward declaration
template <class T = Animal<int> > class Animal //int is just an example
{
public:
T getPrey ();
}
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