How to programmatically determine if the class is a case class or a simple class?

Question

How to programmatically determine if the given class is a case class or a simple class?

Answer 1

Using new Scala reflection API:

scala> class B(v: Int)
defined class B

scala> case class A(v: Int)
defined class A

scala> def isCaseClassOrWhat_?(v: Any): Boolean = {
     |   import reflect.runtime.universe._
     |   val typeMirror = runtimeMirror(v.getClass.getClassLoader)
     |   val instanceMirror = typeMirror.reflect(v)
     |   val symbol = instanceMirror.symbol
     |   symbol.isCaseClass
     | }
isCaseClassOrWhat_$qmark: (v: Any)Boolean

scala> class CaseClassWannabe extends Product with Serializable {
     |   def canEqual(that: Any): Boolean = ???
     |   def productArity: Int = ???
     |   def productElement(n: Int): Any = ???
     | }
defined class CaseClassWannabe

scala> isCaseClassOrWhat_?("abc")
res0: Boolean = false

scala> isCaseClassOrWhat_?(1)
res1: Boolean = false

scala> isCaseClassOrWhat_?(new B(123))
res2: Boolean = false

scala> isCaseClassOrWhat_?(A(321))
res3: Boolean = true

scala> isCaseClassOrWhat_?(new CaseClassWannabe)
res4: Boolean = false