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How to program a fractal?

I do not have any experience with programming fractals. Of course I've seen the famous Mandelbrot images and such.

Can you provide me with simple algorithms for fractals.

Programming language doesn't matter really, but I'm most familiar with actionscript, C#, Java.

I know that if I google fractals, I get a lot of (complicated) information but I would like to start with a simple algorithm and play with it.

Suggestions to improve on the basic algorithm are also welcome, like how to make them in those lovely colors and such.

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Sander Versluys Avatar asked Jan 08 '09 21:01

Sander Versluys


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2 Answers

Programming the Mandelbrot is easy.
My quick-n-dirty code is below (not guaranteed to be bug-free, but a good outline).

Here's the outline: The Mandelbrot-set lies in the Complex-grid completely within a circle with radius 2.

So, start by scanning every point in that rectangular area. Each point represents a Complex number (x + yi). Iterate that complex number:

[new value] = [old-value]^2 + [original-value] while keeping track of two things:

1.) the number of iterations

2.) the distance of [new-value] from the origin.

If you reach the Maximum number of iterations, you're done. If the distance from the origin is greater than 2, you're done.

When done, color the original pixel depending on the number of iterations you've done. Then move on to the next pixel.

public void MBrot() {     float epsilon = 0.0001; // The step size across the X and Y axis     float x;     float y;     int maxIterations = 10; // increasing this will give you a more detailed fractal     int maxColors = 256; // Change as appropriate for your display.      Complex Z;     Complex C;     int iterations;     for(x=-2; x<=2; x+= epsilon)     {         for(y=-2; y<=2; y+= epsilon)         {             iterations = 0;             C = new Complex(x, y);             Z = new Complex(0,0);             while(Complex.Abs(Z) < 2 && iterations < maxIterations)             {                 Z = Z*Z + C;                 iterations++;             }             Screen.Plot(x,y, iterations % maxColors); //depending on the number of iterations, color a pixel.         }     } } 

Some details left out are:

1.) Learn exactly what the Square of a Complex number is and how to calculate it.

2.) Figure out how to translate the (-2,2) rectangular region to screen coordinates.

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abelenky Avatar answered Sep 28 '22 11:09

abelenky


You should indeed start with the Mandelbrot set, and understand what it really is.

The idea behind it is relatively simple. You start with a function of complex variable

f(z) = z2 + C

where z is a complex variable and C is a complex constant. Now you iterate it starting from z = 0, i.e. you compute z1 = f(0), z2 = f(z1), z3 = f(z2) and so on. The set of those constants C for which the sequence z1, z2, z3, ... is bounded, i.e. it does not go to infinity, is the Mandelbrot set (the black set in the figure on the Wikipedia page).

In practice, to draw the Mandelbrot set you should:

  • Choose a rectangle in the complex plane (say, from point -2-2i to point 2+2i).
  • Cover the rectangle with a suitable rectangular grid of points (say, 400x400 points), which will be mapped to pixels on your monitor.
  • For each point/pixel, let C be that point, compute, say, 20 terms of the corresponding iterated sequence z1, z2, z3, ... and check whether it "goes to infinity". In practice you can check, while iterating, if the absolute value of one of the 20 terms is greater than 2 (if one of the terms does, the subsequent terms are guaranteed to be unbounded). If some z_k does, the sequence "goes to infinity"; otherwise, you can consider it as bounded.
  • If the sequence corresponding to a certain point C is bounded, draw the corresponding pixel on the picture in black (for it belongs to the Mandelbrot set). Otherwise, draw it in another color. If you want to have fun and produce pretty plots, draw it in different colors depending on the magnitude of abs(20th term).

The astounding fact about fractals is how we can obtain a tremendously complex set (in particular, the frontier of the Mandelbrot set) from easy and apparently innocuous requirements.

Enjoy!

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Federico A. Ramponi Avatar answered Sep 28 '22 09:09

Federico A. Ramponi