Menu
I can never understand how to print unsigned long datatype in C.
Suppose unsigned_foo is an unsigned long, then I try:
printf("%lu\n", unsigned_foo)printf("%du\n", unsigned_foo)printf("%ud\n", unsigned_foo)printf("%ll\n", unsigned_foo)printf("%ld\n", unsigned_foo)printf("%dl\n", unsigned_foo)And all of them print some kind of -123123123 number instead of unsigned long that I have.
663
%ul will just print unsigned (with %u), and then the letter "l" verbatim. Just as "%uw" will print unsigned, followed by letter "w".
Unsigned long variables are extended size variables for number storage, and store 32 bits (4 bytes). Unlike standard longs unsigned longs won't store negative numbers, making their range from 0 to 4,294,967,295 (2^32 - 1).
To print an unsigned int number, use the %u notation. To print a long value, use the %ld format specifier. You can use the l prefix for x and o, too. So you would use %lx to print a long integer in hexadecimal format and %lo to print in octal format.
The maximum value that can be stored in unsigned long long int is stored as a constant in <climits> header file whose value can be used as ULLONG_MAX. The minimum value that can be stored in unsigned long long int is zero. In case of overflow or underflow of data type, the value is wrapped around.
%lu is the correct format for unsigned long. Sounds like there are other issues at play here, such as memory corruption or an uninitialized variable. Perhaps show us a larger picture?
193
For int %d
For long int %ld
For long long int %lld
For unsigned long long int %llu
45
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With
