I know we can use printf("%04X", value);
to print unsigned hexadecimal values.
Is there a similar flag or a function in C that you can use to print signed hex values?
Something similar like this
Binary Hex (signed) Hex (unsigned)
-------- ----------- --------------
00000010 +0x2 0x2
00000001 +0x1 0x1
00000000 +0x0 0x0
11111111 -0x1 0xFF
11111110 -0x2 0xFE
11111101 -0x3 0xFD
In C programming language, hexadecimal value is represented as 0x or 0X and to input hexadecimal value using scanf which has format specifiers like %x or %X.
A hexadecimal value is int as long as the value fits into int and for larger values it is unsigned , then long , then unsigned long etc. See Section 6.4.
The AHEX format is used to read the hexadecimal representation of standard characters. Each set of two hexadecimal characters represents one standard character. The w specification refers to columns of the hexadecimal representation and must be an even number.
Unfortunately C's printf
function has no way to do this directly. You could of course instead try:
printf("%s%x\n", x<0 ? "-" : "", x<0 ? -(unsigned)x : x);
This should also work for handling INT_MIN.
No, but you can do something like
printf("%c%04X", (x<0) ? '-' : ' ', (x<0) ?-x : x);
But, as other point out, it is doubtful whether there is a valid reason to do so. According to your post, you do understand what you're asking for, so it's all your fault ;-)
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