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I have some number 0.0000002345E^-60. I want to print the floating point value as it is. What is the way to do it? print %f truncates it to 6 digits. Also %n.nf gives fixed numbers. What is the way to print without truncation.
923
To print float values with two decimal places in Python, use the str. format() with “{:. 2f}” as str.
Use a formatted string literal to print a float without scientific notation, e.g. print(f'{num:. 8f}') . You can use an expression in the f-string to print the float without scientific notation, with the specified number of decimal places.
Solution 1: int() Python's built-in function int(x) converts any float number x to an integer by truncating it towards 0. For example, positive int(1.999) will be truncated to 1 and negative int(-1.999) to -1 .
You can control whether to truncate or not by setting the parameter threshold with numpy. set_printoptions() .
Like this?
>>> print('{:.100f}'.format(0.0000002345E-60))
0.0000000000000000000000000000000000000000000000000000000000000000002344999999999999860343602938602754
As you might notice from the output, it’s not really that clear how you want to do it. Due to the float representation you lose precision and can’t really represent the number precisely. As such it’s not really clear where you want the number to stop displaying.
Also note that the exponential representation is often used to more explicitly show the number of significant digits the number has.
You could also use decimal to not lose the precision due to binary float truncation:
>>> from decimal import Decimal
>>> d = Decimal('0.0000002345E-60')
>>> p = abs(d.as_tuple().exponent)
>>> print(('{:.%df}' % p).format(d))
0.0000000000000000000000000000000000000000000000000000000000000000002345
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