i trying to post data as Async with using Guzzle 6(latest ver)
$client = new Client();
$request = $client->postAsync($url, [
'json' => [
'company_name' => 'update Name'
],
]);
but i am not getting any request form Guzzle like post request on terminal
Sending Requests You can create a request and then send the request with the client when you're ready: use GuzzleHttp\Psr7\Request; $request = new Request('PUT', 'http://httpbin.org/put'); $response = $client->send($request, ['timeout' => 2]);
Guzzle allows you to send both asynchronous and synchronous requests using the same interface and no direct dependency on an event loop. This flexibility allows Guzzle to send an HTTP request using the most appropriate HTTP handler based on the request being sent.
// Set various headers on a request $client->request('GET', '/get', [ 'headers' => [ 'User-Agent' => 'testing/1.0', 'Accept' => 'application/json', 'X-Foo' => ['Bar', 'Baz'] ] ]); Headers may be added as default options when creating a client.
Simple usage. use GuzzleLogMiddleware\LogMiddleware; use GuzzleHttp\HandlerStack; $logger = new Logger(); //A new PSR-3 Logger like Monolog $stack = HandlerStack::create(); // will create a stack stack with middlewares of guzzle already pushed inside of it.
Because it's a promise,
you need to put then
and the promise will not called unless you put $promise->wait()
This is a simple post request using postAsync
based on your question:
$client = new Client();
$promise = $client->postAsync($url, [
'json' => [
'company_name' => 'update Name'
],
])->then(
function (ResponseInterface $res){
$response = json_decode($res->getBody()->getContents());
return $response;
},
function (RequestException $e) {
$response = [];
$response->data = $e->getMessage();
return $response;
}
);
$response = $promise->wait();
echo json_encode($response);
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