Here I have a very simple program:
printf("Enter your number in the box below\n");
scanf("%d",&number);
Now, I would like the output to look like this:
Enter your number in the box below
+-----------------+
| |*| |
+-----------------+
Where, |*| is the blinking cursor where the user types their value.
Since C is a linear code, it won't print the box art, then ask for the output, it will print the top row and the left column, then after the input print the bottom row and right column.
So, my question is, could I possibly print the box first, then have a function take the cursor back into the box?
You can make a Windows API (application programming interface) call to a Microsoft Windows DLL (dynamic-link Library) to get and set the current cursor position. The current position can be obtained by using the GetCursorPos function in USER32. DLL.
cursorline = cursorline - 1.
If you are under some Unix terminal (xterm
, gnome-terminal
...), you can use console codes:
#include <stdio.h>
#define clear() printf("\033[H\033[J")
#define gotoxy(x,y) printf("\033[%d;%dH", (y), (x))
int main(void)
{
int number;
clear();
printf(
"Enter your number in the box below\n"
"+-----------------+\n"
"| |\n"
"+-----------------+\n"
);
gotoxy(2, 3);
scanf("%d", &number);
return 0;
}
Or using Box-drawing characters:
printf(
"Enter your number in the box below\n"
"╔═════════════════╗\n"
"║ ║\n"
"╚═════════════════╝\n"
);
More info:
man console_codes
In the linux terminal you may use terminal commands to move your cursor, such as
printf("\033[8;5Hhello"); // Move to (8, 5) and output hello
other similar commands:
printf("\033[XA"); // Move up X lines;
printf("\033[XB"); // Move down X lines;
printf("\033[XC"); // Move right X column;
printf("\033[XD"); // Move left X column;
printf("\033[2J"); // Clear screen
Keep in mind that this is not a standardised solution, and therefore your code will not be platform independent.
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