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Why does the following code compile?
#include <stdio.h>
int main(void) {
getchar;
}
553
A compiler takes the recipe (code) for a new program (written in a high level language) and transforms this Code into a new language (Machine Language) that can be understood by the computer itself.
"Code Snippet" is a term used to describe a small portion of re-usable source code, machine code, or text. They allow a programmer to avoid typing repetitive code during the course of routine programming.
Snippet is a programming term for a small region of re-usable source code, machine code, or text. Ordinarily, these are formally defined operative units to incorporate into larger programming modules.
A compiler takes the program code (source code) and converts the source code to a machine language module (called an object file). Another specialized program, called a linker, combines this object file with other previously compiled object files (in particular run-time modules) to create an executable file.
Because function names are aliases to function pointers to those functions, which are themselves values much like integers.. This is semantically very similar to
#include <stdio.h>
int main(void) {
42;
}
It is valid but pointless.
165
The same reason 1; would compile, getchar is just an address to a function. The result is evaluated, then discarded. In the language specification, it's called an "expression statement";
32
C is weird, this code compiles too, but it segfaults which for the record, is the smallest segfault in C history.
main;
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