I have data from my Facebook, Twitter, Instagram, Youtube, and LinkedIn accounts that I'd like to analyze. I have a data frame similar to the following:
df <- data.frame(tw_likes = c(5,4,6,NA,NA,NA,NA,NA,NA),
tw_comments = c(3,5,NA,NA,NA,NA,NA,NA,NA),
fb_likes = c(NA,NA,NA,7,4,8,NA,NA,NA),
fb_comments = c(NA,NA,NA,NA,NA,7,NA,NA,NA),
ig_likes = c(NA,NA,NA,NA,NA,NA,NA,NA,5),
ig_comments = c(NA,NA,NA,NA,NA,NA,43,4,2))
what I want to do is create an additional column Platform that will take the values of "Twitter, "Facebook, or "Instagram" based on the above dataframe.
My tactic has been the following:
for(i in 1:nrow(df){
if(!is.na(df$tw_likes[i]) | !is.na(df$tw_comments[i])){
df$Platform[i] <- "Twitter"
}
else if(!is.na(df$fb_likes[i]) | !is.na(df$fb_comments[i])){
df$Platform[i] <- "Facebook"
}
else if(!is.na(df$ig_likes[i]) | !is.na(df$ig_comments[i])){
df$Platform[i] <- "Instagram"
}
}
This does work, but becomes messier to read. In reality I have more columns and more social media platforms to deal with, so is there a way to pipe the data so I at least don't have to write df$ so many times?
Another thought I had was if I couldn't remove the df$s, could I combine the !is.na() statements to be one statement per if statement?
Here's an option with dplyr's case_when()
df %>%
mutate(Plataform = case_when(
!is.na(tw_likes) | !is.na(tw_comments) ~ "Twitter",
!is.na(fb_likes) | !is.na(fb_comments) ~ "Facebook",
!is.na(ig_likes) | !is.na(ig_comments) ~ "Instagram"))
Here is one way in base R to split the dataset into a list of same prefix columns (by removing the suffix substring from the column names), do a rowSums to create a logical matrix, apply max.col to get the column position for each row and change that index by passing a vector of replacement values in the same order of split column names
i1 <- max.col(sapply(split.default(df, sub("_.*", "", names(df))),
function(x) rowSums(!is.na(x)) > 0 ), 'first')
df$Platform <- c("Facebook", "Instagram", "Twitter")[i1]
df$Platform
#[1] "Twitter" "Twitter" "Twitter" "Facebook" "Facebook"
#[6] "Facebook" "Instagram" "Instagram" "Instagram"
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