how to pass current year as default argument in php function [duplicate]

Question

I want to pass the current Year as one of the default value of a function

I AM using

date("Y")

for current year

So it work fine when i write function in this way:

function MYfUNCTION($month,$year = 2013)
{
}

But I want to pass current year instead of 2013 but it gives me an error when i write like this

function MYfUNCTION($month,$year = date("Y"))
{
}

Please help me

Answer 1

You can't use a function for a default argument value :

The default value must be a constant expression, not (for example) a variable, a class member or a function call.

(extract from PHP doc)

You should set the default value into the function :

function myFunction($month, $year = null) 
{    
  if(!(bool)$year) {
    $year = date('Y');
  }
  echo $year.', '.$month;
}

myFunction('June', '2006'); // 2006, June
myFunction(3, 2010);        // 2010, 3
myFunction('July');         // 2013, July

Answer 2

You can try this,

function MYfUNCTION($month,$year ="")
{
   if(empty($year)){
      $year = date($year); //Output: current year
   } 

   echo "Year: " . $year ." Month: " . $month;
}

Answer 3

No direct method to pass arguments directly in the pre-defined format, you have to pass function putting the year you want to and you can make 1 more function in which you can change the year. like in php get curr year func. !! hope this can help.