Example:
public void foo(params string[] s) { ... }
We can call this method with:
a) foo("test", "test2", "test3") // multiple single strings
b) foo(new string[]{"test", "test2", "test3"}) // string array
But it is not possible to call the method with:
c) foo("test", new string[]{"test", "test2", "test3"})
So when I have a single string and an array of strings, do I have to put them into one array first to call the method? Or is there a nice workaround to tell the method to consider the string array as single strings?
To pass an entire array to a function, only the name of the array is passed as an argument. result = calculateSum(num); However, notice the use of [] in the function definition. This informs the compiler that you are passing a one-dimensional array to the function.
Arrays can be passed as arguments to method parameters. Because arrays are reference types, the method can change the value of the elements.
If you're passing an array to varargs, and you want its elements to be recognized as individual arguments, and you also need to add an extra argument, then you have no choice but to create another array that accommodates the extra element.
Method 1: Using the apply() method: The apply() method is used to call a function with the given arguments as an array or array-like object. It contains two parameters. The this value provides a call to the function and the arguments array contains the array of arguments to be passed.
While you can solve this without using an extension method, I actually recommend using this extension method as I find it very useful whenever I have a single object but need an IEnumerable<T> that simply returns that single object.
Extension method:
public static class EnumerableYieldExtension
{
public static IEnumerable<T> Yield<T>(this T item)
{
if (item == null)
yield break;
yield return item;
}
}
The extension method is useful in many scenarios. In your case, you can now do this:
string[] someArray = new string[] {"test1", "test2", "test3"};
foo(someArray.Concat("test4".Yield()).ToArray());
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