how to parse a big integer from a string? [duplicate]

Question

I have a method like this:

Integer.parseInt(myInt)

not this integer becomes to long and I'm getting the following exception:

java.lang.NumberFormatException: For input string: "4000123012"

what can I do to avoid this error and still keep alle the functions runnning?

I tried to use BigInteger but there is no parse method, or I did not found it.

Answer 1

Use it like this.

 BigInteger number = new BigInteger(myInt);

Answer 2

My solution :

String sLong = "4000123012";
long yourLong = Long.parseLong(sLong);
System.out.println("Long : "+yourLong);

OutPut :

Long : 4000123012

Answer 3

You can use Long.parse for integers too:

Long.parseLong(myInt)

which of course returns a long.