Say I have a class A and an operator<< declared like so:
// A.h
class A
{
// A stuff
};
std::ostream& operator<<(std::ostream& os, const A& a);
somewhere else I use my logger with A:
LoggerPtr logger(LogManager::getLogger("ThisObject"));
A a;
LOG4CXX_INFO(logger, "A: " << a);
The compiler is complaining: binary '<<' : no operator found which takes a right-hand operand of type 'const A' (or there is no acceptable conversion) D:\dev\cpp\lib\apache-log4cxx\log4cxx\include\log4cxx\helpers\messagebuffer.h 190
This error takes me to the declaration of the operator<<
:
// messagebuffer.h
template<class V>
std::basic_ostream<char>& operator<<(CharMessageBuffer& os, const V& val) {
return ((std::basic_ostream<char>&) os) << val;
}
LOG4XX_INFO
macro expands to:
#define LOG4CXX_INFO(logger, message) { \
if (logger->isInfoEnabled()) {\
::log4cxx::helpers::MessageBuffer oss_; \
logger->forcedLog(::log4cxx::Level::getInfo(), oss_.str(oss_ << message), LOG4CXX_LOCATION); }}
MessageBuffer
"defines" this operator as well:
// messagebuffer.h
template<class V>
std::ostream& operator<<(MessageBuffer& os, const V& val) {
return ((std::ostream&) os) << val;
}
I don't understand how to overload this operator the right way to make it work. Any idea?
Alan's suggestion of putting the user-defined operator in the std
namespace works. But I prefer putting the user-defined operator in the log4cxx::helpers
namespace, which also works. Specifically,
namespace log4cxx { namespace helpers {
ostream& operator<<(ostream& os, const A& a);
} }
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