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I have a file.fa:
>ABC
TGTGTGT
AGAGAGA
TGTAGTA
>BDC
>DTR
>EDF
AGAGGTG
AGTGACA
CAGTGAC
I want to keep the lines without ">", and lines with ">" only if the immediate following line does not have ">":
>ABC
TGTGTGT
AGAGAGA
TGTAGTA
>EDF
AGAGGTG
AGTGACA
CAGTGAC
Looking at the answer for this post, I see that awk '/^>/{x=$0} !/^>/{if(x){print x;x=0;}}' file.fa prints out the header lines (with '>') that I want:
>ABC
>EDF
but how do I also get the lines of text without '>'?
288
Use . readlines() . That code does print out line by line.
go to the (start of the) previous line: \033[F.
The new line character in Python is [&n&]. It is used to indicate the end of a line of text. You can print strings without adding a new line with end = <character>, which <character> is the character that will be used to separate the lines.
Given a text file, read the content of that text file line by line and print only those lines which do not start with defined prefix. Also store those printed lines in another text file. There are following ways in which this task can be done: Method 1: Using loop and startswith ().
When you see a new line in a text file, a new line character \n has been inserted. You can check this by reading the file with <file>.readlines(), like this: with open("names.txt", "r") as f: print(f.readlines()) The output is: As you can see, the first three lines of the text file end with a new line \n character that works "behind the scenes."
We check if that line begins with “Geeks” using regular exapression. If that line begins with “Geeks” we skip that line, and we print the rest of the lines and store those lines in another file.
Using sed:
$ sed '/^>/ { N; /\n>/ D; }' input.txt
>ABC
TGTGTGT
AGAGAGA
TGTAGTA
>EDF
AGAGGTG
AGTGACA
CAGTGAC
If a line starts with >, read the next line and append it to the pattern space. If it also starts with >, delete the first line of the pattern space and repeat with the second line just read as the new input line to look at. Print everything else.
98
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