Python regular expression again - match url

Question

I have such regexp:

 re.compile(r"((https?):((//)|(\\\\))+[\w\d:#@%/;$()~_?\+-=\\\.&]*)", re.MULTILINE|re.UNICODE)

But that doesn't include hashbangs (#!). What I need to change, to get it working? I know I can add ! to group with #@% etc, but that will select something like

Check this out: http://example.com/something/!!!

and I want to avoid that.

Answer 1

Don't try to make your own regular expression for matching URLs, use someone else's who has already solved such problems, like this one.

Answer 2

It could be very long but in practice mine works pretty good. Please try this one ((http|https)\:\/\/)?[a-zA-Z0-9\.\/\?\:@\-_=#]+\.([a-zA-Z]){2,6}([a-zA-Z0-9\.\&\/\?\:@\-_=#])*

It matches all of the example below

http://wwww.stackoverflow.com
abc.com
http://test.test-75.1474.stackoverflow.com/
stackoverflow.com/
stackoverflow.com
[email protected]
http://www.example.com/etcetc
www.example.com/etcetc
example.com/etcetc
user:[email protected]/etcetc
(www.itmag.com)
example.com/etcetc?query=aasd
example.com/etcetc?query=aasd&dest=asds
http://stackoverflow.com/questions/6427530/regular-expression-pattern-to-
match-url-with
www/[email protected]
[email protected].
[email protected] 
[email protected]