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I have been struggling with python regex for a while trying to match paragraphs within a text, but I haven't been successful. I need to obtain the start and end positions of the paragraphs.
An example of a text:
Lorem ipsum dolor sit amet, consetetur sadipscing elitr, sed diam nonumy eirmod
tempor invidunt ut labore et dolore magna aliquyam erat, sed diam voluptua. At
vero eos et accusam et justo duo dolores et ea rebum.
Stet clita kasd gubergren,
no sea takimata sanctus est Lorem ipsum dolor sit amet.
Ipsum dolor sit amet, consetetur sadipscing elitr, sed diam nonumy eirmod
tempor invidunt ut labore et dolore magna aliquyam erat, sed diam voluptua. At
vero eos et accusam et justo duo dolores et ea rebum. Stet clita kasd gubergren,
no sea takimata sanctus est Lorem ipsum dolor sit amet.
In this example case, I would want to separately match all the paragraphs starting with Lorem, Stet and Ipsum respectively (without the empty lines). Does anyone have any idea how to do this?
543
Throw in an * (asterisk), and it will match everything. Read more. \s (whitespace metacharacter) will match any whitespace character (space; tab; line break; ...), and \S (opposite of \s ) will match anything that is not a whitespace character.
If you want to indicate a line break when you construct your RegEx, use the sequence “\r\n”. Whether or not you will have line breaks in your expression depends on what you are trying to match. Line breaks can be useful “anchors” that define where some pattern occurs in relation to the beginning or end of a line.
The dot (or period), . is probably the most used, and certainly the most well-known character class. By default, a dot matches any character, except for the newline.
The RegExp test() Method To check if a string contains only letters and spaces in JavaScript, call the test() method on this regex: /^[A-Za-z\s]*$/ . If the string contains only letters and spaces, this method returns true . Otherwise, it returns false .
You can split on double-newline like this:
paragraphs = re.split(r"\n\n", DATA)
Edit: To capture the paragraphs as matches, so you can get their start and end points, do this:
for match in re.finditer(r'(?s)((?:[^\n][\n]?)+)', DATA):
print match.start(), match.end()
# Prints:
# 0 214
# 215 298
# 299 589
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