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I have a list of objects of say foos. I have a loop for creating a new list.
foo1 = {id:1,location:2}
for e.g. foos = [foo1,foo2,foo3]
Now I want to create a new list based on location.
new_list = []
for foo in foos:
if foo.location==2:
new_list.append(foo)
What I want to know is there any way in which I can do something like this
new_list = []
new_list = map(if foo.location ==2,foos) // this is wrong code but is something like this possible. ?
Can I use map function here ? if yes how ?
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We can club the Python sort() method with the == operator to compare two lists. Python sort() method is used to sort the input lists with a purpose that if the two input lists are equal, then the elements would reside at the same index positions.
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Sure thing you can do it with function. You can use the filter builtin function:
new_list = filter(lambda foo: foo.location == 2, foos)
But the more general and "pythonic" way is to use list comprehensions
new_list = [foo for foo in foos if foo.location == 2]
List comprehension seems to be what you want to use:
new_list = [foo for foo in foos if foo.location == 2]
map is good when you want to apply a function to every item in a list (or any iterable) and get a list of equal length (or an iterator in Python3) as a result. It can't "skip" items based on some condition.
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