How to make number_format() not to round numbers up

Question

I have this number:

$double = '21.188624'; 

After using number_format($double, 2, ',', ' ') I get:

21,19 

But what I want is:

21,18 

Any ideea how can I make this work?

Thank you.

Answer 1

number_format will always do that, your only solution is to feed it something different:

$number = intval(($number*100))/100; 

Or:

$number = floor(($number*100))/100; 

Answer 2

I know that this an old question, but it still actual :) .

How about this function?

function numberFormatPrecision($number, $precision = 2, $separator = '.') {     $numberParts = explode($separator, $number);     $response = $numberParts[0];     if (count($numberParts)>1 && $precision > 0) {         $response .= $separator;         $response .= substr($numberParts[1], 0, $precision);     }     return $response; } 

Usage:

// numbers test numberFormatPrecision(19, 2, '.'); // expected 19 return 19 numberFormatPrecision(19.1, 2, '.'); //expected 19.1 return 19.1 numberFormatPrecision(19.123456, 2, '.'); //expected 19.12 return 19.12 numberFormatPrecision(19.123456, 0, '.'); //expected 19 return 19  // negative numbers test numberFormatPrecision(-19, 2, '.'); // expected -19 return -19 numberFormatPrecision(-19.1, 2, '.'); //expected -19.1 return -19.1 numberFormatPrecision(-19.123456, 2, '.'); //expected -19.12 return -19.12 numberFormatPrecision(-19.123456, 0, '.'); //expected -19 return -19  // precision test numberFormatPrecision(-19.123456, 4, '.'); //expected -19.1234 return -19.1234  // separator test numberFormatPrecision('-19,123456', 3, ','); //expected -19,123 return -19,123  -- comma separator