How to make a variadic macro for std::cout?

Question

How would I make a macro that took a variable amount of arguments, and prints its out using std::cout? Sorry if this is a noob question, couldn't find anything that clarified variadic macros after searching around for the answer.

Conceptual Example:

#include <iostream>
#define LOG(...) std::cout << ... << ... << std::endl
int main() {
    LOG("example","output","filler","text");
    return 0;
}

would output:

exampleoutputfillertext

Answer 1

You do not need preprocessor macros to do this. You can write it in ordinary C++. In C++11/14:

#include <iostream>
#include <utility>

void log(){}

template<typename First, typename ...Rest>
void log(First && first, Rest && ...rest)
{
    std::cout << std::forward<First>(first);
    log(std::forward<Rest>(rest)...);
}

int main()
{
    log("Hello", "brave","new","world!\n");
    log("1", 2,std::string("3"),4.0,'\n');
}

Live demo

In C++17:

template<typename ...Args>
void log(Args && ...args)
{
    (std::cout << ... << args);
}

is all it takes. Live demo

Output:

Hellobravenewworld!
1234

Research variadic templates, parameter packs and fold expressions rather than variadic macros, which are rarely useful in modern C++.