Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

How to make a ListBox.ItemTemplate reusable/generic

I am trying to understand how best to extend the ListBox control. As a learning experience, I wanted to build a ListBox whose ListBoxItems display a CheckBox instead of just text. I got that working in a basic fashion using the ListBox.ItemTemplate, explicitly setting the names of the properties I wanted to databind to. An example is worth a thousand words, so...

I've got a custom object for databinding:

public class MyDataItem {
    public bool Checked { get; set; }
    public string DisplayName { get; set; }

    public MyDataItem(bool isChecked, string displayName) {
        Checked = isChecked;
        DisplayName = displayName;
    }
}

(I build a list of those and set ListBox.ItemsSource to that list.) And my XAML looks like this:

<ListBox Name="listBox1">
    <ListBox.ItemTemplate>
        <DataTemplate>
            <CheckBox IsChecked="{Binding Path=Checked}" Content="{Binding Path=DisplayName}" />
        </DataTemplate>
    </ListBox.ItemTemplate>
</ListBox>

This works. But I want to make this template reusable, i.e. I'll want to bind to other objects with properties other than "Checked" and "DisplayName". How can I modify my template such that I could make it a resource, reuse it on multiple ListBox instances, and for each instance, bind IsChecked and Content to arbitrary property names?

like image 898
Matt Winckler Avatar asked Mar 23 '09 23:03

Matt Winckler


3 Answers

Create your DataTemplate as a resource and then reference it using the ItemTemplate property of the ListBox. MSDN has a good example

<Windows.Resources>
  <DataTemplate x:Key="yourTemplate">
    <CheckBox IsChecked="{Binding Path=Checked}" Content="{Binding Path=DisplayName}" />
  </DataTemplate>
...
</Windows.Resources>

...
<ListBox Name="listBox1"
         ItemTemplate="{StaticResource yourTemplate}"/>
like image 198
MrTelly Avatar answered Oct 04 '22 15:10

MrTelly


The easiest way is probably to put the DataTemplate as a resource somewhere in your application with a TargetType of MyDataItem like this

<DataTemplate DataType="{x:Type MyDataItem}">
    <CheckBox IsChecked="{Binding Path=Checked}" Content="{Binding Path=DisplayName}" />
</DataTemplate>

You'll probably also have to include an xmlns to your local assembly and reference it through that. Then whenever you use a ListBox (or anything else that uses a MyDataItem in a ContentPresenter or ItemsPresenter) it will use this DataTemplate to display it.

like image 29
Bryan Anderson Avatar answered Oct 04 '22 15:10

Bryan Anderson


If you wanted one way display then you could use a converter:

class ListConverter : IValueConverter
{
    public object Convert(object value, Type targetType, object parameter, System.Globalization.CultureInfo culture)
    {
        return ((IList<MyDataItem>)value).Select(i => new { Checked = i.Checked2, DisplayName = i.DisplayName2 });
    }

    public object ConvertBack(object value, Type targetType, object parameter, System.Globalization.CultureInfo culture)
    {
        throw new NotImplementedException();
    }
}

Then the xaml would look something like this:

<Window.Resources>
    <this:ListConverter x:Key="ListConverter" />
</Window.Resources>
<ListBox ItemsSource="{Binding Path=Items, Converter={StaticResource ListConverter}}">
    <ListBox.ItemTemplate>
        <DataTemplate>
            <CheckBox IsChecked="{Binding Path=Checked, Mode=OneWay}" Content="{Binding Path=DisplayName, Mode=OneWay}" />
        </DataTemplate>
    </ListBox.ItemTemplate>
</ListBox>

That data template you could make generic like above. Two way binding would be a fair bit more difficult.

I think you are better off making your base classes implement a ICheckedItem interface which exposes the generic properties that you want the datatemplates to bind to?

like image 35
Jake Ginnivan Avatar answered Oct 04 '22 16:10

Jake Ginnivan