Is there a shortcut to make a simple list out of a list of lists in Python?
I can do it in a for
loop, but is there some cool "one-liner"?
I tried it with functools.reduce()
:
from functools import reduce l = [[1, 2, 3], [4, 5, 6], [7], [8, 9]] reduce(lambda x, y: x.extend(y), l)
But I get this error:
Traceback (most recent call last): File "<stdin>", line 1, in <module> File "<stdin>", line 1, in <lambda> AttributeError: 'NoneType' object has no attribute 'extend'
In Python, use list methods clear() , pop() , and remove() to remove items (elements) from a list. It is also possible to delete items using del statement by specifying a position or range with an index or slice.
Given a list of lists t
,
flat_list = [item for sublist in t for item in sublist]
which means:
flat_list = [] for sublist in t: for item in sublist: flat_list.append(item)
is faster than the shortcuts posted so far. (t
is the list to flatten.)
Here is the corresponding function:
def flatten(t): return [item for sublist in t for item in sublist]
As evidence, you can use the timeit
module in the standard library:
$ python -mtimeit -s't=[[1,2,3],[4,5,6], [7], [8,9]]*99' '[item for sublist in t for item in sublist]' 10000 loops, best of 3: 143 usec per loop $ python -mtimeit -s't=[[1,2,3],[4,5,6], [7], [8,9]]*99' 'sum(t, [])' 1000 loops, best of 3: 969 usec per loop $ python -mtimeit -s't=[[1,2,3],[4,5,6], [7], [8,9]]*99' 'reduce(lambda x,y: x+y,t)' 1000 loops, best of 3: 1.1 msec per loop
Explanation: the shortcuts based on +
(including the implied use in sum
) are, of necessity, O(T**2)
when there are T sublists -- as the intermediate result list keeps getting longer, at each step a new intermediate result list object gets allocated, and all the items in the previous intermediate result must be copied over (as well as a few new ones added at the end). So, for simplicity and without actual loss of generality, say you have T sublists of k items each: the first k items are copied back and forth T-1 times, the second k items T-2 times, and so on; total number of copies is k times the sum of x for x from 1 to T excluded, i.e., k * (T**2)/2
.
The list comprehension just generates one list, once, and copies each item over (from its original place of residence to the result list) also exactly once.
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