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Difference between staticmethod and classmethod

What is the difference between a function decorated with @staticmethod and one decorated with @classmethod?

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Daryl Spitzer Avatar asked Sep 25 '08 21:09

Daryl Spitzer


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What is the difference between Classmethod and Staticmethod?

The class method takes cls (class) as first argument. The static method does not take any specific parameter. Class method can access and modify the class state. Static Method cannot access or modify the class state.

What is the difference between @classmethod and @staticmethod decorators?

The difference between the Class method and the static method is: A class method takes cls as the first parameter while a static method needs no specific parameters. A class method can access or modify the class state while a static method can't access or modify it.

What does Staticmethod mean?

A static method (or static function) is a method defined as a member of an object but is accessible directly from an API object's constructor, rather than from an object instance created via the constructor.

When should Staticmethod be used?

staticmethods can be used when the code that belongs to a class doesn't use the object itself at all. Python doesn't have to instantiate a bound method for each object we instantiate. Bound methods are objects too, and creating them has a cost. Having a static method avoids that.


1 Answers

Maybe a bit of example code will help: Notice the difference in the call signatures of foo, class_foo and static_foo:

class A(object):     def foo(self, x):         print(f"executing foo({self}, {x})")      @classmethod     def class_foo(cls, x):         print(f"executing class_foo({cls}, {x})")      @staticmethod     def static_foo(x):         print(f"executing static_foo({x})")  a = A() 

Below is the usual way an object instance calls a method. The object instance, a, is implicitly passed as the first argument.

a.foo(1) # executing foo(<__main__.A object at 0xb7dbef0c>, 1) 

With classmethods, the class of the object instance is implicitly passed as the first argument instead of self.

a.class_foo(1) # executing class_foo(<class '__main__.A'>, 1) 

You can also call class_foo using the class. In fact, if you define something to be a classmethod, it is probably because you intend to call it from the class rather than from a class instance. A.foo(1) would have raised a TypeError, but A.class_foo(1) works just fine:

A.class_foo(1) # executing class_foo(<class '__main__.A'>, 1) 

One use people have found for class methods is to create inheritable alternative constructors.


With staticmethods, neither self (the object instance) nor cls (the class) is implicitly passed as the first argument. They behave like plain functions except that you can call them from an instance or the class:

a.static_foo(1) # executing static_foo(1)  A.static_foo('hi') # executing static_foo(hi) 

Staticmethods are used to group functions which have some logical connection with a class to the class.


foo is just a function, but when you call a.foo you don't just get the function, you get a "partially applied" version of the function with the object instance a bound as the first argument to the function. foo expects 2 arguments, while a.foo only expects 1 argument.

a is bound to foo. That is what is meant by the term "bound" below:

print(a.foo) # <bound method A.foo of <__main__.A object at 0xb7d52f0c>> 

With a.class_foo, a is not bound to class_foo, rather the class A is bound to class_foo.

print(a.class_foo) # <bound method type.class_foo of <class '__main__.A'>> 

Here, with a staticmethod, even though it is a method, a.static_foo just returns a good 'ole function with no arguments bound. static_foo expects 1 argument, and a.static_foo expects 1 argument too.

print(a.static_foo) # <function static_foo at 0xb7d479cc> 

And of course the same thing happens when you call static_foo with the class A instead.

print(A.static_foo) # <function static_foo at 0xb7d479cc> 
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unutbu Avatar answered Sep 29 '22 12:09

unutbu