how to 'ls' another directory in unix script?

Question

My code

echo $ls | /var/lib/judgem/records/

I'm trying to get the script to show me all the files inside the folder "records"

How do I do that?

Answer 1

Or, if you want to list the contents of another directory without the full path, i.e. as though you were in the other directory, but without ending up there after the command has finished, you can use a subshell like this:

(cd /var/lib/judgem/records/ && ls)

You will notice you stay in whatever directory you were in but the files are listed without the full path of /var/lib/judgem/records on the front.

Answer 2

Give the directory as the argument to ls:

ls /var/lib/judgem/records