I'm trying to join the same table in sqlalchemy. This is a minimial version of what I tried:
#!/usr/bin/env python
import sqlalchemy as sa
from sqlalchemy import create_engine
from sqlalchemy.orm import mapper, sessionmaker, aliased
engine = create_engine('sqlite:///:memory:', echo=True)
metadata = sa.MetaData()
device_table = sa.Table("device", metadata,
sa.Column("device_id", sa.Integer, primary_key=True),
sa.Column("name", sa.String(255), nullable=False),
sa.Column("parent_device_id", sa.Integer, sa.ForeignKey('device.device_id')),
)
class Device(object):
device_id = None
def __init__(self, name, parent_device_id=None):
self.name = name
self.parent_device_id = parent_device_id
def __repr__(self):
return "<Device(%s, '%s', %s)>" % (self.device_id,
self.name,
self.parent_device_id )
mapper(Device, device_table)
metadata.create_all(engine)
db_session = sessionmaker(bind=engine)()
parent = Device('parent')
db_session.add(parent)
db_session.commit()
child = Device('child', parent.device_id)
db_session.add(child)
db_session.commit()
ParentDevice = aliased(Device, name='parent_device')
q = db_session.query(Device, ParentDevice)\
.outerjoin(ParentDevice,
Device.parent_device_id==ParentDevice.device_id)
print list(q)
This gives me this error:
ArgumentError: Can't determine join between 'device' and 'parent_device'; tables have more than one foreign key constraint relationship between them. Please specify the 'onclause' of this join explicitly.
But I am specifying a onclause
for the join. How should I be doing this?
For query.[outer]join
, you specify as list of joins (which is different to expression.[outer]join
.) So I needed to put the 2 elements of the join, the table and the onclause
in a tuple, like this:
q = db_session.query(Device, ParentDevice)\
.outerjoin(
(ParentDevice, Device.parent_device_id==ParentDevice.device_id)
)
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