How to Java String.format with a variable precision?

Question

I'd like to vary the precision of a double representation in a string I'm formatting based on user input. Right now I'm trying something like:

String foo = String.format("%.*f\n", precision, my_double); 

however I receive a java.util.UnknownFormatConversionException. My inspiration for this approach was C printf and this resource (section 1.3.1).

Do I have a simple syntax error somewhere, does Java support this case, or is there a better approach?

Edit:

I suppose I could do something like:

String foo = String.format("%." + precision + "f\n", my_double); 

but I'd still be interested in native support for such an operation.

Answer 1

You sort of answered your own question - build your format string dynamically... valid format strings follow the conventions outlined here: http://java.sun.com/j2se/1.5.0/docs/api/java/util/Formatter.html#syntax.

If you want a formatted decimal that occupies 8 total characters (including the decimal point) and you wanted 4 digits after the decimal point, your format string should look like "%8.4f"...

To my knowledge there is no "native support" in Java beyond format strings being flexible.

Answer 2

You can use the DecimalFormat class.

double d1 = 3.14159; double d2 = 1.235;  DecimalFormat df = new DecimalFormat("#.##");  double roundedD1 = df.format(d); // 3.14 double roundedD2 = df.format(d); // 1.24 

If you want to set the precision at run time call:

df.setMaximumFractionDigits(precision)