I have an XML structure along the lines of:
<root>
<SomeElement>
<AnotherElement>
<ElementIWant x="1" y="1"/>
</AnotherElement>
</SomeElement>
<SomeElement>
<AnotherElement>
<ElementIWant x="1" y="1"/>
<ElementIWant x="2" y="1"/>
<ElementIWant x="3" y="1"/>
</AnotherElement>
</SomeElement>
</root>
Which is being read into a boost::property_tree
, There are 1..Many <SomeElement>
s, and then at an arbitrary depth within that element there could be 1..Many <ElementIWant>
s
Is there a way to iterate over the <ElementIWant>
directly (in a single loop) in the order that they appear in the doc?
I have looked at equal_range
void iterateOverPoints()
{
const char* test =
"<?xml version=\"1.0\" encoding=\"utf-8\"?><root>"
"<SomeElement>"
"<AnotherElement>"
"<ElementIWant x=\"1\" y=\"1\"/>"
"</AnotherElement>"
"</SomeElement>"
"<SomeElement>"
"<AnotherElement>"
"<ElementIWant x=\"1\" y=\"1\"/>"
"<ElementIWant x=\"2\" y=\"1\"/>"
"<ElementIWant x=\"3\" y=\"1\"/>"
"</AnotherElement>"
"</SomeElement>"
"</root>";
boost::property_tree::ptree message;
std::istringstream toParse(test);
boost::property_tree::read_xml(toParse,result_tree);
//Now we need to locate the point elements and set the x/y accordingly.
std::pair< boost::property_tree::ptree::const_assoc_iterator,
boost::property_tree::ptree::const_assoc_iterator > result =
message.equal_range("ElementIWant");
for( boost::property_tree::ptree::const_assoc_iterator it = result.first;
it != result.second; ++it )
{
std::cout << it->first << " : ";
const boost::property_tree::ptree& x = it->second.get_child( "<xmlattr>.x" );
const boost::property_tree::ptree& y = it->second.get_child( "<xmlattr>.y" );
std::cout << x.get_value<int>() << "," << y.get_value<int>() << "\n";
}
return;
}
However it seems to fail to return nodes (Which I suspect is because equal_range works at the level of the tree node supplied) Which brings me to the question above...
It is not possible to iterate over all elements directly; the documentation says
There is no way to iterate over the entire tree.
Now, you could use recursion, and apply STL algorithms at each level to mimic that; it does not fit your requirement of doing this in a single loop in my sample below, but it does works:
template <typename InputIt, typename OutputIt, typename Compare>
void collect(InputIt first, InputIt last, OutputIt dest, Compare comp)
{
typedef typename std::iterator_traits<InputIt>::reference reference;
std::copy_if (
first, last, dest,
[comp] (reference what) { return comp(what.first); });
std::for_each (
first, last,
[dest, comp] (reference what) { collect(what.second.begin(), what.second.end(), dest, comp); });
}
std::vector<std::pair<std::string, ptree>> match;
collect(
xml.begin (), xml.end (), std::back_inserter(match),
[] (const std::string& key) { return key == "ElementIWant"; });
for (auto pair: match)
{
std::cout << pair.first << std::endl;
}
Here is a version that is "fully" recursive and preserve the order of appearance:
template <typename InputIt, typename OutputIt, typename Compare>
void collect_recursive(InputIt first, InputIt last, OutputIt dest, Compare comp)
{
typedef typename std::iterator_traits<InputIt>::reference reference;
if (first == last)
{
return;
}
auto begin = first->second.begin ();
auto end = first->second.end ();
if (begin != end)
{
collect_recursive (begin, end, dest, comp);
}
if (comp (first->first))
{
dest = *first;
}
collect_recursive (++first, last, dest, comp);
}
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