1 Answer. You can use File#isDirectory() to test if the given file (path) is a directory. If this is true, then you just call the same method again with its File#listFiles() outcome. This is called recursion.
If you have the directory name in myDirectoryPath
,
import java.io.File;
...
File dir = new File(myDirectoryPath);
File[] directoryListing = dir.listFiles();
if (directoryListing != null) {
for (File child : directoryListing) {
// Do something with child
}
} else {
// Handle the case where dir is not really a directory.
// Checking dir.isDirectory() above would not be sufficient
// to avoid race conditions with another process that deletes
// directories.
}
I guess there are so many ways to make what you want. Here's a way that I use. With the commons.io
library you can iterate over the files in a directory. You must use the FileUtils.iterateFiles
method and you can process each file.
You can find the information here: http://commons.apache.org/proper/commons-io/download_io.cgi
Here's an example:
Iterator it = FileUtils.iterateFiles(new File("C:/"), null, false);
while(it.hasNext()){
System.out.println(((File) it.next()).getName());
}
You can change null
and put a list of extentions if you wanna filter. Example: {".xml",".java"}
Here is an example that lists all the files on my desktop. you should change the path variable to your path.
Instead of printing the file's name with System.out.println, you should place your own code to operate on the file.
public static void main(String[] args) {
File path = new File("c:/documents and settings/Zachary/desktop");
File [] files = path.listFiles();
for (int i = 0; i < files.length; i++){
if (files[i].isFile()){ //this line weeds out other directories/folders
System.out.println(files[i]);
}
}
}
Use java.io.File.listFiles
Or
If you want to filter the list prior to iteration (or any more complicated use case), use apache-commons FileUtils. FileUtils.listFiles
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