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For static generic methods, the type parameter section must appear before the method's return type. The complete syntax for invoking this method would be: Pair<Integer, String> p1 = new Pair<>(1, "apple"); Pair<Integer, String> p2 = new Pair<>(2, "pear"); boolean same = Util. <Integer, String>compare(p1, p2);
1 Answer. You can't use a class's generic type parameters in static methods or static fields. The class's type parameters are only in scope for instance methods and instance fields.
When a generic method is called, the compiler determines the actual types to use for the type parameters from the context. Comparable<T> is. is an interface defined in the Java class libraries.
Yes, this is type inference based on the target of the assignment, as per JLS section 15.12.2.8. To be explicit, you'd call something like:
Foo.<String>createFoo();
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