How to insert strings containing slashes with sed? [duplicate]

Question

The easiest way would be to use a different delimiter in your search/replace lines, e.g.:

s:?page=one&:pageone:g

You can use any character as a delimiter that's not part of either string. Or, you could escape it with a backslash:

s/\//foo/

Which would replace / with foo. You'd want to use the escaped backslash in cases where you don't know what characters might occur in the replacement strings (if they are shell variables, for example).

The s command can use any character as a delimiter; whatever character comes after the s is used. I was brought up to use a #. Like so:

s#?page=one&#/page/one#g

A very useful but lesser-known fact about sed is that the familiar s/foo/bar/ command can use any punctuation, not only slashes. A common alternative is s@foo@bar@, from which it becomes obvious how to solve your problem.

add \ before special characters:

s/\?page=one&/page\/one\//g

etc.

In a system I am developing, the string to be replaced by sed is input text from a user which is stored in a variable and passed to sed.

As noted earlier on this post, if the string contained within the sed command block contains the actual delimiter used by sed - then sed terminates on syntax error. Consider the following example:

This works:

$ VALUE=12345
$ echo "MyVar=%DEF_VALUE%" | sed -e s/%DEF_VALUE%/${VALUE}/g
MyVar=12345

This breaks:

$ VALUE=12345/6
$ echo "MyVar=%DEF_VALUE%" | sed -e s/%DEF_VALUE%/${VALUE}/g
sed: -e expression #1, char 21: unknown option to `s'

Replacing the default delimiter is not a robust solution in my case as I did not want to limit the user from entering specific characters used by sed as the delimiter (e.g. "/").

However, escaping any occurrences of the delimiter in the input string would solve the problem. Consider the below solution of systematically escaping the delimiter character in the input string before having it parsed by sed. Such escaping can be implemented as a replacement using sed itself, this replacement is safe even if the input string contains the delimiter - this is since the input string is not part of the sed command block:

$ VALUE=$(echo ${VALUE} | sed -e "s#/#\\\/#g")
$ echo "MyVar=%DEF_VALUE%" | sed -e s/%DEF_VALUE%/${VALUE}/g
MyVar=12345/6

I have converted this to a function to be used by various scripts:

escapeForwardSlashes() {

     # Validate parameters
     if [ -z "$1" ]
     then
             echo -e "Error - no parameter specified!"
             return 1
     fi

     # Perform replacement
     echo ${1} | sed -e "s#/#\\\/#g"
     return 0
}

this line should work for your 3 examples:

sed -r 's#\?(page)=([^&]*)&#/\1/\2#g' a.txt

• I used -r to save some escaping .
• the line should be generic for your one, two three case. you don't have to do the sub 3 times

test with your example (a.txt):

kent$  echo "?page=one&
?page=two&
?page=three&"|sed -r 's#\?(page)=([^&]*)&#/\1/\2#g'
/page/one
/page/two
/page/three

please see this article http://netjunky.net/sed-replace-path-with-slash-separators/

Just using | instead of /