I use Jquery Clone for adding more form for filling data. then i want to add all data of form individually in a new row of database. database table will be.ex. according my array.
name | author | category
ABC 2 1
XYZ 2 1
PQR 5 2
my array
Array
(
[Book] => Array
(
[name] => Array
(
[0] => ABC
[1] => XYZ
[2] => PQR
)
[author] => Array
(
[0] => 2
[1] => 2
[2] => 5
)
[category] => Array
(
[0] => 1
[1] => 1
[2] => 2
)
)
)
you will have to put your data in saveAll compatible format like this
array(
'Book' => array(
0 => array(
'name' => 'xxx',
'author' => 'yyy',
),
1 => array(
'name' => 'aaa',
'author' => 'bbb',
)
)
)
you can do that by traforming your jquery clone passed data. something like this. Note: not tested
$data = array();
$names = Hash::extract($jquerycloneData,'Book.name');//array(ABC,XYZ,PQR);
$authors = Hash::extract($jquerycloneData,'Book.author');
$categories = Hash::extract($jquerycloneData,'Book.category');
$i=0;
for($i, $i<count($names) ,$i++){
$data['Book'][$i]['name'] = $names[$i];
$data['Book'][$i]['author'] = $authors[$i];
$data['Book'][$i]['category'] = $categories[$i];
}
then simply call saveAll in your Book model
$this->saveAll($data);
assuming your data arrived in the format you provided above
Generate the form fields with names like -
echo $this->Form->input('Book.0.name');
echo $this->Form->input('Book.1.name');
echo $this->Form->input('Book.0.author');
echo $this->Form->input('Book.1.author');
Then You will get the data like -
array(
'Book' => array(
0 => array(
'name' => 'xxx',
'author' => 'yyy',
),
1 => array(
'name' => 'aaa',
'author' => 'bbb',
)
)
)
Then the saveMany() will work with them properly.
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