How to include file in a bash shell script

Question

Simply put inside your script :

source FILE

Or

. FILE # POSIX compliant

$ LANG=C help source
source: source filename [arguments]
Execute commands from a file in the current shell.

Read and execute commands from FILENAME in the current shell.  The
entries in $PATH are used to find the directory containing FILENAME.
If any ARGUMENTS are supplied, they become the positional parameters
when FILENAME is executed.

Exit Status:
Returns the status of the last command executed in FILENAME; fails if
FILENAME cannot be read.

Above answers are correct, but if you run script in another folder, there will be some problem.

For example, a.sh and b.sh are in same folder, a use . ./b.sh to include b.

When you run script out of the folder, for example, xx/xx/xx/a.sh, file b.sh will not found: ./b.sh: No such file or directory.

So I use

. $(dirname "$0")/b.sh

Yes, use source or the short form which is just .:

. other_script.sh

Syntax is source <file-name>

ex. source config.sh

script - config.sh

USERNAME="satish"
EMAIL="[email protected]"

calling script -

#!/bin/bash
source config.sh
echo Welcome ${USERNAME}!
echo Your email is ${EMAIL}.

You can learn to include a bash script in another bash script here.

In my situation, in order to include color.sh from the same directory in init.sh, I had to do something as follows.

. ./color.sh

Not sure why the ./ and not color.sh directly. The content of color.sh is as follows.

RED=`tput setaf 1`
GREEN=`tput setaf 2`
BLUE=`tput setaf 4`
BOLD=`tput bold`
RESET=`tput sgr0`

Making use of File color.sh does not error but, the color do not display. I have tested this in Ubuntu 18.04 and the Bash version is:

GNU bash, version 4.4.19(1)-release (x86_64-pc-linux-gnu)