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I have a large text file, I want to see the lines containing "time spent" in this text file, I use:
grep -in "time spent" myfile.txt But I'm interested only in the lines after 50000. In the output I want to see lines after 50000 and that contain "time spent". Is there a way to do this?
798
You can use grep with -A n option to print N lines after matching lines. Using -B n option you can print N lines before matching lines. Using -C n option you can print N lines before and after matching lines.
The -n ( or --line-number ) option tells grep to show the line number of the lines containing a string that matches a pattern. When this option is used, grep prints the matches to standard output prefixed with the line number.
The grep command searches through the file, looking for matches to the pattern specified. To use it type grep , then the pattern we're searching for and finally the name of the file (or files) we're searching in. The output is the three lines in the file that contain the letters 'not'.
To Display Line Numbers with grep MatchesAppend the -n operator to any grep command to show the line numbers. We will search for Phoenix in the current directory, show two lines before and after the matches along with their line numbers.
You can tail it, then grep:
tail -n +50000 myfile.txt | grep -in "time spent" If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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