Converting byte array values in little endian order to short values

Question

I have a byte array where the data in the array is actually short data. The bytes are ordered in little endian:

3, 1, -48, 0, -15, 0, 36, 1

Which when converted to short values results in:

259, 208, 241, 292

Is there a simple way in Java to convert the byte values to their corresponding short values? I can write a loop that just takes every high byte and shift it by 8 bits and OR it with its low byte, but that has a performance hit.

Answer 1

With java.nio.ByteBuffer you may specify the endianness you want: order().

ByteBuffer have methods to extract data as byte, char, getShort(), getInt(), long, double...

Here's an example how to use it:

ByteBuffer bb = ByteBuffer.wrap(byteArray); bb.order( ByteOrder.LITTLE_ENDIAN); while( bb.hasRemaining()) {    short v = bb.getShort();    /* Do something with v... */ } 

Answer 2

 /* Try this: */ public static short byteArrayToShortLE(final byte[] b, final int offset)  {         short value = 0;         for (int i = 0; i < 2; i++)          {             value |= (b[i + offset] & 0x000000FF) << (i * 8);         }                      return value;  }   /* if you prefer... */  public static int byteArrayToIntLE(final byte[] b, final int offset)   {         int value = 0;          for (int i = 0; i < 4; i++)          {            value |= ((int)b[i + offset] & 0x000000FF) << (i * 8);         }         return value;  }