How to Get XML Node from XDocument

Question

test.xml:

<?xml version="1.0" encoding="utf-8"?>
<Contacts>
  <Node>
    <ID>123</ID>
    <Name>ABC</Name>
  </Node>
  <Node>
    <ID>124</ID>
    <Name>DEF</Name>
  </Node>
</Contacts>

Select a single node:

XDocument XMLDoc = XDocument.Load("test.xml");
string id = "123"; // id to be selected

XElement Contact = (from xml2 in XMLDoc.Descendants("Node")
                    where xml2.Element("ID").Value == id
                    select xml2).FirstOrDefault();

Console.WriteLine(Contact.ToString());

Delete a single node:

XDocument XMLDoc = XDocument.Load("test.xml");
string id = "123";

var Contact = (from xml2 in XMLDoc.Descendants("Node")
               where xml2.Element("ID").Value == id
               select xml2).FirstOrDefault();

Contact.Remove();
XMLDoc.Save("test.xml");

Add new node:

XDocument XMLDoc = XDocument.Load("test.xml");

XElement newNode = new XElement("Node",
    new XElement("ID", "500"),
    new XElement("Name", "Whatever")
);

XMLDoc.Element("Contacts").Add(newNode);
XMLDoc.Save("test.xml");

The .Elements operation returns a LIST of XElements - but what you really want is a SINGLE element. Add this:

XElement Contacts = (from xml2 in XMLDoc.Elements("Contacts").Elements("Node")
                    where xml2.Element("ID").Value == variable
                    select xml2).FirstOrDefault();

This way, you tell LINQ to give you the first (or NULL, if none are there) from that LIST of XElements you're selecting.

Marc