How to get UDID of iPhone? [duplicate]

Question

I want unique device ID for iPhone that remains unchanged?, I want Unique device ID that cannot be changed if I uninstall application and install again on same device. I am Using swift 2.1.1 and xcode 7.2.1. I have tried this code but both will not work.

//First approach

let device_id = UIDevice.currentDevice().identifierForVendor!.UUIDString
print("unique device id: (device_id)")

//Second approach

let dID = CFUUIDCreate(kCFAllocatorDefault)
let deviceID = CFUUIDCreateString(kCFAllocatorDefault, dID) as NSString
print("unique CFUUID id: (deviceID)")

Answer 1

Swift 3.X Latest simple usage;

if let identifierForVendor = UIDevice.current.identifierForVendor {
    print(identifierForVendor.uuidString)
}

Answer 2

This is working in swift 3 / Xcode / Iphone7 for me.

let deviceUUID: String = (UIDevice.current.identifierForVendor?.uuidString)!

Answer 3

Use this

let UUID = CFUUIDCreateString(nil, CFUUIDCreate(nil))
 func application(application: UIApplication!, didFinishLaunchingWithOptions launchOptions: NSDictionary!) -> Bool {

let userDefaults = NSUserDefaults.standardUserDefaults()

if userDefaults.objectForKey("ApplicationUniqueIdentifier") == nil {
    let UUID = NSUUID.UUID().UUIDString
    userDefaults.setObject(UUID, forKey: "ApplicationUniqueIdentifier")
    userDefaults.synchronize()
}
return true

}

This will work correctly in swift

Answer 4

Try this ,

UIDevice.currentDevice().identifierForVendor

or if you want a string:

UIDevice.currentDevice().identifierForVendor.UUIDString
print(UIDevice.currentDevice().identifierForVendor().UUIDString()) //Print Log