If I have a type type foo = Array<{ name: string; test: number; }>
, would it be possible to get the type of the values within the array, in this case, the interface. I know there is keyof
to get the keys, is there something similar for values?
You shouldn't use the typeof operator to check whether a value is an array, because typeof cannot distinguish between arrays and objects. Instead you should use Array. isArray() , because typeof would return 'object' , not 'array' . Array.
It includes Set , ArrayList , Queue , etc. You will not be wrong, an array is indeed a collection of objects, although like you said it does not implement the Collection interface. That said people usually refer to stuff that implements Collection when they say collection.
get() is an inbuilt method in Java and is used to return the element at a given index from the specified Array. Parameters : This method accepts two mandatory parameters: array: The object array whose index is to be returned.
In typescript, an array is a data type that can store multiple values of different data types sequentially. Similar to JavaScript, Typescript supports array declaration and there are multiple ways to do it. Declaring and Initializing Arrays: We can either use var or let for declaring an array.
If you're looking to how to extract { name: string; test: number; }
type, you can simply create alias to "item at index":
type Foo = Array<{ name: string; test: number; }>;
type FooItem = Foo[0];
or
type FooItem = Foo[number];
Starting with TypeScript 2.8 you can also do this inline with the infer
keyword:
type GetElementType<T extends any[]> = T extends (infer U)[] ? U : never;
For example:
// ElementType === string
type ElementType = string[] extends (infer U)[] ? U : never;
The infer
keyword is very powerful and can extract any type out of larger type. For example if the type was a function that returns an array:
type FncType = () => [{ name: string }];
// Output === { name: string }
type Output = FncType extends () => (infer U)[] ? U : never;
You can also use the infer keyword in generic types:
type GetArrayReturnType<T> = T extends () => (infer U)[] ? U : never;
// Output === { name: string }
type Output = GetArrayReturnType<() => [{ name: string }]>;
We can also use an indexed access operator like this:
const someArray = [
{
foo: '',
bar: '',
baz: ''
},
{
foo: '',
bar: '',
baz: ''
}
];
// indexed access operator
type SomeArray = typeof someArray[number];
There is a write-up on those here: https://www.typescriptlang.org/docs/handbook/advanced-types.html
The second operator is T[K], the indexed access operator.
Despite Aleksey answer, it might be useful to know that if the instance of that generic type exposes at least one member of the type you want to extract, you could use typeof
to query the type of that member.
For a generic Array
the type can be queried from any array item:
Note that line 27 only exists at design time so that will not generate any errors even if arr
is empty or undefined at runtime.
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