In matlab, if you have a matrix A
you can find the matrix B
containing all of the unique rows of A
as follows:
B = unique(A,'rows');
What I have is a 3d matrix, with rows and columns as the first two dimensions, and one additional dimension ('slices').
How can I get the 3d matrix containing all the unique slices in a matrix A
? Here's an example of the kind of functionality I want:
>> A % print out A
A(:,:,1) =
16 2 3 13
5 11 10 8
9 7 6 12
4 14 15 1
A(:,:,2) =
1 0 0 0
0 1 0 0
0 0 1 0
0 0 0 1
A(:,:,3) =
16 2 3 13
5 11 10 8
9 7 6 12
4 14 15 1
A(:,:,4) =
0 0 0 1
0 0 1 0
0 1 0 0
1 0 0 0
>> unique(A,'slices'); % get unique slices
A(:,:,1) =
16 2 3 13
5 11 10 8
9 7 6 12
4 14 15 1
A(:,:,2) =
1 0 0 0
0 1 0 0
0 0 1 0
0 0 0 1
A(:,:,3) =
0 0 0 1
0 0 1 0
0 1 0 0
1 0 0 0
I would begin by reshaping A so each slice becomes a row (with the reshape
command). Then use unique(A, 'rows')
. Finally, reshape the unique rows back to the same shape the slices.
For example:
% transforming so each row is a slice in row form
reshaped_A = reshape(A, [], size(A, 3))';
% getting unique rows
unique_rows = unique(reshaped_A, 'rows');
% reshaping back
unique_slices = reshape(unique_rows', size(A, 1), size(A, 2), []);
Or all in one line:
reshape(unique(reshape(A, [], size(A, 3))', 'rows')', size(A, 1), size(A, 2), [])
I haven't checked this above code so use with caution! But it should give the idea.
EDIT
Here it is working on your data (also fixed little bug in above code):
>> reshaped_A = reshape(A, [], size(A, 3))'
reshaped_A =
Columns 1 through 11
16 5 9 4 2 11 7 14 3 10 6
1 0 0 0 0 1 0 0 0 0 1
16 5 9 4 2 11 7 14 3 10 6
0 0 0 1 0 0 1 0 0 1 0
Columns 12 through 16
15 13 8 12 1
0 0 0 0 1
15 13 8 12 1
0 1 0 0 0
Each of these ^^ rows is one of the original slices
>> unique_rows = unique(reshaped_A, 'rows')
unique_rows =
Columns 1 through 11
0 0 0 1 0 0 1 0 0 1 0
1 0 0 0 0 1 0 0 0 0 1
16 5 9 4 2 11 7 14 3 10 6
Columns 12 through 16
0 1 0 0 0
0 0 0 0 1
15 13 8 12 1
These ^^ are the unique slices, but in the wrong shape.
>> unique_slices = reshape(unique_rows', size(A, 1), size(A, 2), [])
unique_slices(:,:,1) =
0 0 0 1
0 0 1 0
0 1 0 0
1 0 0 0
unique_slices(:,:,2) =
1 0 0 0
0 1 0 0
0 0 1 0
0 0 0 1
unique_slices(:,:,3) =
16 2 3 13
5 11 10 8
9 7 6 12
4 14 15 1
A very simple and scalable solution would be:
A = cat(3, [16 2 3 13;5 11 10 8;9 7 6 12;4 14 15 1], [1 0 0 0;0 1 0 0;0 0 1 0;0 0 0 1], [16 2 3 13;5 11 10 8;9 7 6 12;4 14 15 1], [0 0 0 1;0 0 1 0;0 1 0 0;1 0 0 0])
[n,m,p] = size(A);
a = reshape(A,n,[],1);
b = reshape(a(:),n*m,[])';
c = unique(b,'rows', 'stable')'; %If the 'stable' option is supported by your version.
%If the 'stable' option is not supported, but it's still required, use the index vector option, as required.
%i.e.,
%[c,I,J] = unique(b,'rows');
unique_A = reshape(c,n,m,[])
Results:
A(:,:,1) =
16 2 3 13
5 11 10 8
9 7 6 12
4 14 15 1
A(:,:,2) =
1 0 0 0
0 1 0 0
0 0 1 0
0 0 0 1
A(:,:,3) =
16 2 3 13
5 11 10 8
9 7 6 12
4 14 15 1
A(:,:,4) =
0 0 0 1
0 0 1 0
0 1 0 0
1 0 0 0
unique_A(:,:,1) =
0 0 0 1
0 0 1 0
0 1 0 0
1 0 0 0
unique_A(:,:,2) =
1 0 0 0
0 1 0 0
0 0 1 0
0 0 0 1
unique_A(:,:,3) =
16 2 3 13
5 11 10 8
9 7 6 12
4 14 15 1
Source: How to find unique pages in a 3d matrix?
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