How to get the size of a const char pointer

Question

const char *array[] = {"ax","bo","cf"};

tried

printf("size of array = %lu\n", sizeof(const char*));

result != 3

also

printf("size of array = %lu\n", sizeof(array));
result != **DESIRED ANSWER** = 4

NOTE... I have read related questions on here but none had a relation with my question......

Answer 1

To get the size of a const char pointer:`

printf("%zu\n", sizeof(const char *));

To get the size of the array array[]:

const char *array[] = {"ax","bo","cf"};
printf("%zu\n", sizeof array);

To get the number of elements in the array array[], divide the size of the array by the size of an array element.

const char *array[] = {"ax","bo","cf"};
// Size of array/size of array element
printf("%zu\n", sizeof array / sizeof array[0]); 
// expect 3