C String manipulation pointer vs array notation [duplicate]

Question

Why does the first version make the program crash, while the second one doesn't? Aren't they the same thing?

Pointer Notation

char *shift = "mondo";
shift[3] = shift[2];

---

Array Notation

char shift[] = {'m', 'o', 'n', 'd', 'o', '\0'};
shift[3] = shift[2];

---

MWE

int main( void )
{
    char *shift = "mondo";
    shift[3] = shift[2];

    char shift[] = {'m', 'o', 'n', 'd', 'o', '\0'};
    shift[3] = shift[2];

    return 0;
}

Answer 1

No! This is one of the important issues in C. In the first, you create a pointer to a read-only part of memory, i.e. you can not change it, only read it. The second, makes an array of characters, i.e. a part of memory of continuous characters where you can have both read and write access, meaning you can both read and change the values of the array.