How to get the first and last second in python using datetime module

Question

How to get the first and last second in python using datetime module which means 00:00:01 and 23:59:59.

I want to get the six datetime before today.

So, for example:

today 12/10, and I want to get

12/9 00:00:01 and 23:59:59

...

12/4 00:00:01 and 23:59:59

Thank you very much.

Answer 1

Just use datetime.time.min and datetime.time.max:

>>> import datetime
>>> datetime.time.min
datetime.time(0, 0)
>>> datetime.time.max
datetime.time(23, 59, 59, 999999)

You can combine that with a datetime.date instance to get a full datetime.datetime instance:

>>> datetime.datetime.combine(datetime.date.today(), datetime.time.max)
datetime.datetime(2012, 12, 1, 23, 59, 59, 999999)

To re-use an existing datetime.datetime instance, use the .combine() method together with the .date() method on the datetime.datetime instance to create a new datetime.datetime instance:

>>> datetime.datetime.combine(datetime.datetime.now().date(), datetime.time.min)
datetime.datetime(2012, 12, 1, 0, 0)

To get a series of dates, use datetime.timedelta instances to create offsets. A series of dates relative to today is then easy:

today = datetime.date.today()
lastweek = today - datetime.timedelta(days=7)
for i in range(7):
    aday = lastweek + datetime.timedelta(days=i)
    first = datetime.datetime.combine(aday, datetime.time.min)
    last = datetime.datetime.combine(aday, datetime.time.max)
    print first, last